!*************************************************************************************!
! TITLE: CFVR0926 - Shell shear reinforcement design according to Eurocode 2 (1991)
! SUBTITLE: Shell shear reinforcement design according to Eurocode 2 (1991).
!
! DESCRIPTION: The model is made up of two square shell elements of 1.0m x 1.0m.
! DESCRIPTION: The nodes of one side are completely restrained and one of the nodes
! DESCRIPTION: between both element has its vertical movement restrained
! DESCRIPTION: (perpendicular to the shells).
! DESCRIPTION:
! DESCRIPTION: There is no initial shear reinforcement.
! DESCRIPTION:
! DESCRIPTION: The applied loads is a pressure of 3 kg/cm<sup>2</sup> on one of the elements.
! DESCRIPTION:
! DESCRIPTION:
! DESCRIPTION: The reinforcement design code is the Eurocode 2 (1991).
! DESCRIPTION:
!
! ELEMENT TYPE: Shell43
! MODULES:
! UNITS: User
! KEYWORD1: Shell
! KEYWORD2: Shell Vertex
! KEYWORD3: Reinforced Concrete
! KEYWORD4: Eurocode 2
!*************************************************************************************!
   FINISH
  ~cfclear,,1
   NomFile='CFVR0926'
  /TITLE, %NomFile%, Shell shear reinforcement design according to Eurocode 2 (1991)
! ---------------------------------------------------------------------------------
! Model definition and solve
! ---------------------------------------------------------------------------------

! Setup
 ~UNITS,,MONE,EURO
 ~UNITS,,LENG,CM
 ~UNITS,,TIME,S
 ~UNITS,,FORC,KP
 ~CODESEL,,EC2-91,
 ~CFCONFG,PLRES   ,SHELL   ,EPSW 
 ~CFCONFG,RESULT,CFSHF,1

  /PREP7
! Materials
  ~CFMP,5,LIB,CONCRETE,EC2,C40/50
  ~CFMP,2,LIB,REINF,EC2,S400
! Element types
  ET,2,SHELL43
! Shell Vertex
  t=25     ! Thickness
  r=4   ! Cover
  th = 0   ! Reinforcement angle
 ~SHLRNF,1,t,5,2,r,0.0,0.0,0.0,0.0,0,th,45
 ~SHLSHR,1,2,,12,,,14,14
! Beam & Shell property
 ~BMSHPRO,10,SHELL,1,1,1,1,43,,,,Shell property

! Nodes
  N,10,0,0
  N,20,100,0
  N,30,200,0
  N,40,0,100
  N,50,100,100
  N,60,200,100
! Elements
  MAT,5
  REAL,10
  TYPE,2
  EN,100, 10, 20, 50, 40
  EN,200, 20, 30, 60, 50
! Boundary conditions
  D,10,ALL,0.0
  D,40,ALL,0.0
  D,50,UZ,0.0
! Solve
  /SOLU
  SFE,100,2,PRES,,3.0
  SOLVE

  /POST1
! ---------------------------------------------------------------------------------
! Design with CivilFEM
! ---------------------------------------------------------------------------------
 ~CFSET,,1
 ~DIMCON,SHELL,SHEAR
 ~CFSET,1

!--------------------------------------------------------------------------------------
! DATA CHECK
!--------------------------------------------------------------------------------------
! Data comparison number
  NComp = 11
  NComp_ch = 0

! Matrix dim.
  *DIM,LABEL,CHAR,Ncomp,1
  *DIM,LABEL_CH,CHAR,Ncomp_ch,1
  *DIM,VALUE,,Ncomp,3
  *DIM,VALUE_CH,CHAR,Ncomp_ch,3
  *DIM,TOLER,,Ncomp,2

! Labels
!--------------------------------------------------------------------------------------
  LABEL( 1,1) = 'VRD1'
  LABEL( 2,1) = 'CRVRD1'
  LABEL( 3,1) = 'VRD2'
  LABEL( 4,1) = 'CRVRD2'
  LABEL( 5,1) = 'ASST'
  LABEL( 6,1) = 'ASSH'
  LABEL( 7,1) = 'VRD1'
  LABEL( 8,1) = 'CRVRD1'
  LABEL( 9,1) = 'VRD2'
  LABEL(10,1) = 'CRVRD2'
  LABEL(11,1) = 'ASSB'

! Correct values
  VALUE( 1,1)=146.446
  VALUE( 2,1)=1.942
  VALUE( 3,1)=1284.842
  VALUE( 4,1)=0.2213
  VALUE( 5,1)=0.0401
  VALUE( 6,1)=0.00206
  VALUE( 7,1)=146.446
  VALUE( 8,1)=0.2189
  VALUE( 9,1)=1284.842
  VALUE(10,1)=0.02496
  VALUE(11,1)=0.00452

! Comparison
 ESEL,S,ELEM,,100
 ~PLSHCON,VRD1
 *GET,VALUE(1,2),NODE,10,EPSW
 ~PLSHCON,CRVRD1
 *GET,VALUE(2,2),NODE,10,EPSW
 ~PLSHCON,VRD2
 *GET,VALUE(3,2),NODE,10,EPSW
 ~PLSHCON,CRVRD2
 *GET,VALUE(4,2),NODE,10,EPSW
 ~PLSHCON,ASST
 *GET,VALUE(5,2),NODE,10,EPSW
 ~PLSHCON,ASSH
 *GET,VALUE(6,2),NODE,10,EPSW
 ESEL,S,ELEM,,200
 ~PLSHCON,VRD1
 *GET,VALUE(7,2),NODE,20,EPSW
 ~PLSHCON,CRVRD1
 *GET,VALUE(8,2),NODE,20,EPSW
 ~PLSHCON,VRD2
 *GET,VALUE(9,2),NODE,20,EPSW
 ~PLSHCON,CRVRD2
 *GET,VALUE(10,2),NODE,20,EPSW
 ~PLSHCON,ASSB
 *GET,VALUE(11,2),NODE,20,EPSW

! Warning and error tolerances
  *DO,II,1,NComp
    TOLER(II,1)= 1E-03 $ TOLER(II,2)= 1E-03
  *ENDDO
  TOLER( 6,1)= 1E-05 $ TOLER( 6,2)= 1E-05

!--------------------------------------------------------------------------------------
! Results comparison
!--------------------------------------------------------------------------------------
  COMPARA.MAC