CFVR0852 - Linear combination test
Example to check the linear combinations utility
This example checks the functionality of the combinations module.
It checks the following:
- Linear combinations.
- Date handle with unsorted numeration (elements, load steps...)
The load cases are:
- Load Step 1: Surface load (1 N/m) on Span 1.
- Load Step 2: Surface load (2 N/m) on Span 2.
- Load Step 3: Surface load (3 N/m) on Span 3.
- Combination rule 18: Addition [3.0*H1 + 2.0*H2]
- Combination rule 28: Addition [Combination 1 + 5.0*H3]
Element types used in the model: BEAM3 Needed CivilFEM Modules: |
|
| Model Statistics | |
| Number of elements | 6 |
| Number of nodes | 12 |
| Number of civil materials | 13 |
| Number of cross sections | 1 |
| Number of shell vertices | 0 |
Log file: CFVR0852.DAT
FINISH ~CFCLEAR,,1 AnsLic='ansys' NomFile='CFVR0852' /TITLE, %NomFile%, Linear combination test ! --------------------------------------------------------------------------------- ! Model definition and solve ! --------------------------------------------------------------------------------- ! Load scheme: ! LS1 Q=1 LS2 Q=2 LS3 Q=3 ! |||||||||||||||||| ||||||||||||||||| ||||||||||||||||||| ! |||||||||||||||||| ||||||||||||||||| ||||||||||||||||||| ! vvvvvvvvvvvvvvvvvv vvvvvvvvvvvvvvvvv vvvvvvvvvvvvvvvvvvv ! 2 4 6 8 10 12 14 : Nodes ! o=========o=========o=========o=========o=========o=========o ! ^ 5 7 ^ 9 11 ^ 13 15 ^ : Elements ! 3 5 7 9 11 13 : Material ! 2 4 6 8 10 12 : Section ! 4 4 6 6 8 8 : Types ! 3 3 3 3 3 3 : Ename ! |------ 10 m -------|------ 16 m -------|------ 10 m -------| ! --------------------------------------------------------------------------------- ~UNITS,,LENG,M ~UNITS,,TIME,S ~UNITS,,FORC,KN ~CODESEL,EC3,EC2-91,EC2-91,,EC8-94 /PREP7 ! Materials *DO,IMAT,2,14 ~CFMP,IMAT,LIB,STEEL,EA,A42 *ENDDO ! Element types ET,1,BEAM3 *DO,ITYP,2,10,4 ET,ITYP,BEAM3 *ENDDO *DO,ITYP,4,12,4 ET,ITYP,BEAM3 *ENDDO ! Sections ~SSECLIB,1,2,1,6 ! IPE 180 ! Beam & Shell Property *DO,ISEC,1,13 ~BMSHPRO,ISEC,BEAM,1,1,,,3,1,0 *ENDDO ! Nodes N, 1,-1 N, 2, 0 N, 4, 5 N, 6,10 N,10,26 FILL,6,10 N,14,36 FILL,10,14 ! Elements MAT, 3 $ REAL, 2 $ TYPE, 4 $ EN, 5, 2, 4 MAT, 5 $ REAL, 4 $ TYPE, 4 $ EN, 7, 4, 6 MAT, 7 $ REAL, 6 $ TYPE, 6 $ EN, 9, 6, 8 MAT, 9 $ REAL, 8 $ TYPE, 6 $ EN,11, 8,10 MAT,11 $ REAL,10 $ TYPE, 8 $ EN,13,10,12 MAT,13 $ REAL,12 $ TYPE, 8 $ EN,15,12,14 ! Boundary conditions D,2,UX D,2,UY D,6,UY D,10,UY D,14,UY ! Initial hypothesis solve /SOLU SOLCONTROL,OFF AUTOTS,OFF ! Hypothesis 1: LS1 Q=1 (1st Span) /TITLE, H1: LS1 SFBEAM, 5,1,PRES,1,1 SFBEAM, 7,1,PRES,1,1 SOLVE SFEDELE,ALL,ALL,PRES ! Hypothesis 2: LS2 Q=2 (2nd Span) /TITLE, H2: LS2 SFBEAM, 9,1,PRES,2,2 SFBEAM,11,1,PRES,2,2 SOLVE SFEDELE,ALL,ALL,PRES ! Hypothesis 3: LS3 Q=3 (3rd Span) /TITLE, H3: LS3 SFBEAM,13,1,PRES,3,3 SFBEAM,15,1,PRES,3,3 SOLVE SFEDELE,ALL,ALL,PRES /POST1 ! --------------------------------------------------------------------------------- ! Definition and solving of combinations ! --------------------------------------------------------------------------------- ! Reset combinations module ~CMBCLR ! Combinations definition ! Combination 18: ADDITION [3H1+2H2] ~CMBDEF,18,ADD,2 ~STSTDEF,18,1,LSTEP,1 ! H1: LS1 Q=1 (1st Span) ~STSTDEF,18,2,LSTEP,2 ! H2: LS2 Q=2 (2nd Span) ~STSTCFT,18,1,3.00 ~STSTCFT,18,2,2.00 ! Combination 28: ADDITION CMB1+5H3 = [3H1+2H2]+5H3 ~CMBDEF,28,ADD,2 ~STSTDEF,28,1,CMB,18 ! Cmb1 ~STSTDEF,28,2,LSTEP,3 ! H3: LS3 Q=3 (3rd Span) ~STSTCFT,28,1,1.00 ~STSTCFT,28,2,5.00 ~LINCMB !-------------------------------------------------------------------------------------- ! DATA CHECK !-------------------------------------------------------------------------------------- ! Data comparison number NComp = 12 NComp_ch = 0 ! Matrix dim. *DIM,LABEL,CHAR,Ncomp,1 *DIM,LABEL_CH,CHAR,Ncomp_ch,1 *DIM,VALUE,,Ncomp,3 *DIM,VALUE_CH,CHAR,Ncomp_ch,3 *DIM,TOLER,,Ncomp,2 ! Correct values ! --------------------------------------------------------------------------------- VALUE( 1,1) = 62.250 VALUE( 2,1) = -425398.63 VALUE( 3,1) = -0.202570778E-2 VALUE( 4,1) = 34.6764706 VALUE( 5,1) = -236969.044 VALUE( 6,1) = -0.112842403E-2 VALUE( 7,1) = 62.250 VALUE( 8,1) = -425398.63 VALUE( 9,1) = -0.202570778E-2 VALUE(10,1) = 34.6764706 VALUE(11,1) = -236969.044 VALUE(12,1) = -0.112842403E-2 ! Obtained values ! --------------------------------------------------------------------------------- ! Test 1: ~CFSET,,4 ETABLE,MZ_I,SMISC,6 ETABLE,MZ_J,SMISC,12 ! Comparison *GET,VALUE(1,2),ELEM,9,ETAB,MZ_J ! Test 2: ~CFSET,,4 ETABLE,SX_I,LS ,2 ETABLE,SX_J,LS ,5 ! Comparison *GET,VALUE(2,2),ELEM,9,ETAB,SX_J ! Test 3: ~CFSET,,4 ! Comparison ETABLE,EP_I,LEPEL,2 ETABLE,EP_J,LEPEL,5 *GET,VALUE(3,2),ELEM,9,ETAB,EP_J ! Test 4: ~CFSET,,5 ! Comparison ETABLE,MZ_I,SMISC,6 ETABLE,MZ_J,SMISC,12 *GET,VALUE(4,2),ELEM,9,ETAB,MZ_J ! Test 5: ~CFSET,,5 ! Comparison ETABLE,SX_I,LS ,2 ETABLE,SX_J,LS ,5 *GET,VALUE(5,2),ELEM,9,ETAB,SX_J ! Test 6: ~CFSET,,5 ! Comparison ETABLE,EP_I,LEPEL,2 ETABLE,EP_J,LEPEL,5 *GET,VALUE(6,2),ELEM,9,ETAB,EP_J ! Test 7: ~CFSET,,4 ! Comparison ~PLLSFOR,M,Z *GET,VALUE(7,2),ELEM,9,ETAB,CFETAB_J ! Test 8: ~CFSET,,4 ! Comparison ~PLLSSTR,SX,25 *GET,VALUE(8,2),ELEM,9,ETAB,CFETAB_J ! Test 9: ~CFSET,,4 ! Comparison ~PLLSSTR,EPX,25 *GET,VALUE(9,2),ELEM,9,ETAB,CFETAB_J ! Test 10: ~CFSET,,5 ! Comparison ~PLLSFOR,M,Z *GET,VALUE(10,2),ELEM,9,ETAB,CFETAB_J ! Test 11: ~CFSET,,5 ! Comparison ~PLLSSTR,SX,25 *GET,VALUE(11,2),ELEM,9,ETAB,CFETAB_J ! Test 12: ~CFSET,,5 ! Comparison ~PLLSSTR,EPX,25 *GET,VALUE(12,2),ELEM,9,ETAB,CFETAB_J ! Labels ! --------------------------------------------------------------------------------- *DO,II,1,12 LABEL(II) ='TEST%II%' *ENDDO ! Warning and error tolerances TOLER( 1, 1)= 1E-5 $ TOLER( 1, 2)= 1E-4 TOLER( 2, 1)= 1E-1 $ TOLER( 2, 2)= 1E-0 TOLER( 3, 1)= 1E-5 $ TOLER( 3, 2)= 1E-4 TOLER( 4, 1)= 1E-5 $ TOLER( 4, 2)= 1E-4 TOLER( 5, 1)= 1E-1 $ TOLER( 5, 2)= 1E-0 TOLER( 6, 1)= 1E-5 $ TOLER( 6, 2)= 1E-4 TOLER( 7, 1)= 1E-5 $ TOLER( 7, 2)= 1E-4 TOLER( 8, 1)= 1E-2 $ TOLER( 8, 2)= 1E-1 TOLER( 9, 1)= 1E-5 $ TOLER( 9, 2)= 1E-4 TOLER(10, 1)= 1E-5 $ TOLER(10, 2)= 1E-4 TOLER(11, 1)= 1E-2 $ TOLER(11, 2)= 1E-1 TOLER(12, 1)= 1E-5 $ TOLER(12, 2)= 1E-4 !-------------------------------------------------------------------------------------- ! Results comparison !-------------------------------------------------------------------------------------- COMPARA.MAC |
Results
| Label | Target | CivilFEM | Ratio | Tolerance |
| TEST1 | 62.25 | 62.25 | 1.000 | 0.0001 |
| TEST2 | -4.254e+005 | -4.254e+005 | 1.000 | 1 |
| TEST3 | -0.0020257 | -0.0020257 | 1.000 | 0.0001 |
| TEST4 | 34.676 | 34.676 | 1.000 | 0.0001 |
| TEST5 | -2.3697e+005 | -2.3697e+005 | 1.000 | 1 |
| TEST6 | -0.0011284 | -0.0011284 | 1.000 | 0.0001 |
| TEST7 | 62.25 | 62.25 | 1.000 | 0.0001 |
| TEST8 | -4.254e+005 | -4.254e+005 | 1.000 | 0.1 |
| TEST9 | -0.0020257 | -0.0020257 | 1.000 | 0.0001 |
| TEST10 | 34.676 | 34.676 | 1.000 | 0.0001 |
| TEST11 | -2.3697e+005 | -2.3697e+005 | 1.000 | 0.1 |
| TEST12 | -0.0011284 | -0.0011284 | 1.000 | 0.0001 |
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