Left

CivilFEM Online Help

Right

CFVR1217 - Shear design according to Eurocode 2 (1991)

Design a reinforced concrete beam subjected to Shear force according to Eurocode 2 (1991)

A beam which is fixed at the right and simply supported at the left, has a T reinforced concrete section and it is subjected to a uniform distributed load of 84 kN/m.
The aim of the example is to obtain the necessary steel amount according to Eurocode 2 (1991).
The example is based on "DESIGNERS' HANDBOOK TO EUROCODE 2", BEEBY AND NARAYANAN, 1995, PAGE 97, EX.6.1

Element types used in the model: BEAM3

Needed CivilFEM Modules:
Geotechnical Module
Bridges and Civil Non Linearities Module
Advanced Prestressed Concrete Module

The example can be launched on an educational license.
KEYWORDS
Beam
Cross Section
Code Checking/Design
Reinforced Concrete
Eurocode 2

Model Statistics
Number of elements 25
Number of nodes 26
Number of civil materials 2
Number of cross sections 1
Number of shell vertices 0

Log file: CFVR1217.DAT


   FINISH
  ~CFCLEAR,,1
   NomFile='CFVR1217'
 /TITLE,%NomFile% Shear design according to Eurocode 2 (1991)

! -------------------------------------------------------------------------------------
! Initial data
! -------------------------------------------------------------------------------------
! CivilFEM SETUP
  ~UNITS,,LENG,M
  ~UNITS,,TIME,S
  ~UNITS,,FORC,KN
  ~CODESEL,EC3-92,EC2-91,EC2-91,,EC8-94

! Preprocessor
  /PREP7

! Parameters
  L=5          ! Length between supports, in m
  Q=84         ! Uniform distributed load in kN/m

! Material Definition
 ~CFMP,1,LIB,CONCRETE,EC2,C25/30
 ~CFMP,2,LIB,REINF,EC2,S500

! Element Type Definition
  ET,1,Beam3                            ! Element Type 1: 2D Beam

! Cross-section definition
 ~CSECDMS,1,T,1,0.375,0.15,0.75,0.15    !T Section
! Reinforcement definition
 ~RNFDEF,1,1,2,1,1,0.02,0.2200E-02      !Longitudinal reinforcement
 ~RNFMDF,1,1,UFC,2
 ~RNFDEF,1,SHEAR,2,,,1.0E-4,            !Shear reinforcement

! Code properties definition
 ~SECMDF,1,EC2PROP ,REC     ,,5e-002    !5cm Cover
 ~SECMDF,1,EC2PROP ,D_Y     ,,0.325     !automatically calculated when changing Gc
 ~SECMDF,1,EC2PROP ,RHO1    ,,0.02      !RHO value for shear
! Beam properties
  ~BMSHPRO,1,BEAM,1,1,,,3,1,,,

! Model Construction
  N,1                                   ! Nodes input
  N,26,L
  FILL,1,26

  E,1,2                                 ! Elements input
  EGEN,25,1,1,1

  D,1, , , , , ,UX,UY                   ! Constraint conditions
  D,26, , , , , ,UY

/SOLU
  SFBEAM,ALL,1,PRES,Q
  SOLVE               ! Calculation

/POST1

! Postprocessor
  ~CFSET,,1,1       ! Read first load step

! Shear in Y design according to EC2
  ~DIMCON,SHT,SHEAR

!--------------------------------------------------------------------------------------
! DATA CHECK
!--------------------------------------------------------------------------------------
! Data comparison number
  NComp = 3
  NComp_ch = 0

! Matrix dim.
  *DIM,LABEL,CHAR,Ncomp,1
  *DIM,LABEL_CH,CHAR,Ncomp_ch,1
  *DIM,VALUE,,Ncomp,3
  *DIM,VALUE_CH,CHAR,Ncomp_ch,3
  *DIM,TOLER,,Ncomp,2

! Labels
  LABEL(1,1) = 'VRD1'
  LABEL(2,1) = 'VRD2'
  LABEL(3,1) = 'ASSH'

! Correct values
  VALUE(1,1)=0.373E2
  VALUE(2,1)=0.21023E3
  VALUE(3,1)=0.10937778E-2

! Comparison
 ~PLLSCON,VRD1
 *GET,VALUE(1,2),ELEM,2,ETAB,CFETAB_J
 ~PLLSCON,VRD2
  *GET,VALUE(2,2),ELEM,2,ETAB,CFETAB_J
 ~PLLSCON,ASSH
  *GET,VALUE(3,2),ELEM,2,ETAB,CFETAB_J

! Warning and error tolerances
  TOLER( 1, 1)= 1E-02 $ TOLER( 1, 2)= 1E-02
  TOLER( 2, 1)= 1E-02 $ TOLER( 2, 2)= 1E-02
  TOLER( 3, 1)= 1E-06 $ TOLER( 3, 2)= 1E-06

!--------------------------------------------------------------------------------------
! Results comparison
!--------------------------------------------------------------------------------------
  COMPARA.MAC

Results

LabelTargetCivilFEMRatioTolerance
VRD1 37.3 37.2941.000 0.01
VRD2 210.23 210.231.000 0.01
ASSH 0.0010938 0.00109381.000 1e-006


Contains proprietary and confidential information of Ingeciber, S.A.