CFVR7909 - CTE DB SE-A test: Compression Buckling
Compression Buckling checking according to CTE DB SE-A
A fixed steel beam subjected to a Fy load of -250 KN.
The beam has a length of 1 m.
The cross section is a L 100 x 100 x 12.
The beam is made of Fe 460 steel which has a fy of 460000 kN/m2.
The aim of the example is to obtain the cross section classification and compression buckling criterion according to CTE DB SE-A.
Element types used in the model: BEAM4 Needed CivilFEM Modules: |
|
| Model Statistics | |
| Number of elements | 24 |
| Number of nodes | 25 |
| Number of civil materials | 1 |
| Number of cross sections | 1 |
| Number of shell vertices | 0 |
Log file: CFVR7909.DAT
FINISH ~CFCLEAR,,1 NomFile='CFVR7909' /TITLE, %NomFile%, CTE DB SE-A test: Compression Buckling ! --------------------------------------------------------------------------------- ! Model definition and solve ! --------------------------------------------------------------------------------- ! CivilFEM Setup: Code & Units ~UNITS,,LENG,M ~UNITS,,TIME,S ~UNITS,,FORC,KN ~CODESEL,CTESEA,EC2,,,EC8-94 /PREP7 ! Preprocessor ! -------------------------------------------------- ! Materials ~CFMP,1,LIB,STEEL,UNE,S 460 ! Element Types ET,1,BEAM4 ! Type 1: 3D Beam ! Cross Sections ~SSECLIB,1,1,23,6 ! L 100 x 100 x 12 ! Member properties ~MEMBPRO,1,CTESEA,ALL,10,1.0,1.0,1,1,1,1,0.8,1,1.0,1.0,0 ! Beam properties ~BMSHPRO,1,BEAM,1,,,,4,1,0,, ! Nodes N, 1 N,25,,10 FILL, 1,25 ! Elements E,1,2 EGEN,24,1,1 EPLOT /SOLU ! Solution ! -------------------------------------------------- ! Displacements D, 1,UX D, 1,UY D, 1,UZ D,25,UX D,25,UZ D,ALL,ROTY ! Apply Load F,25,FY,-250 ! Solve SOLVE /POST1 ! Postprocessor ! -------------------------------------------------- ! Read results ~CFSET,,1,1 ! Read the first load step ! Eurocode No.3 Check Buckling Compression ~CHKSTL,BUCK_CMP,-Z,PARTIAL !-------------------------------------------------------------------------------------- ! DATA CHECK !-------------------------------------------------------------------------------------- ! Data comparison number NComp = 8 NComp_ch = 0 ! Matrix dim. *DIM,LABEL,CHAR,Ncomp,1 *DIM,LABEL_CH,CHAR,Ncomp_ch,1 *DIM,VALUE,,Ncomp,3 *DIM,VALUE_CH,CHAR,Ncomp_ch,3 *DIM,TOLER,,Ncomp,2 ! Labels !-------------------------------------------------------------------------------------- LABEL( 1,1) = 'CLASS' LABEL( 2,1) = 'ALP_Z' LABEL( 3,1) = 'AREA' LABEL( 4,1) = 'LAM_Z' LABEL( 5,1) = 'PHI_Z' LABEL( 6,1) = 'CHI_Z' LABEL( 7,1) = 'NBRD' LABEL( 8,1) = 'CRT_TOT' ! Correct values 2 UPN section !-------------------------------------------------------------------------------------- ! VALUE( 1,1)= 1 ! VALUE( 2,1)= 0.34 ! VALUE( 3,1)= 2.271E-3 ! VALUE( 4,1)= 4.938 ! VALUE( 5,1)= 13.47 ! VALUE( 6,1)= 0.03844 ! VALUE( 7,1)= 38.25 ! VALUE( 8,1)= 6.53 ! Correct values I section !-------------------------------------------------------------------------------------- ! VALUE( 1,1)= 3 ! VALUE( 2,1)= 0.34 ! VALUE( 3,1)= 2.271e-3 ! VALUE( 4,1)= 4.9337 ! VALUE( 5,1)= 13.47 ! VALUE( 6,1)= 0.03844 ! VALUE( 7,1)= 38.25 ! VALUE( 8,1)= 6.53 ! Correct values L section !-------------------------------------------------------------------------------------- VALUE( 1,1)= 3 VALUE( 2,1)= 0.34 VALUE( 3,1)= 2.271e-3 VALUE( 4,1)= 4.9337 VALUE( 5,1)= 13.47 VALUE( 6,1)= 0.03844 VALUE( 7,1)= 38.25 VALUE( 8,1)= 6.53 ! Obtained values !-------------------------------------------------------------------------------------- ~PLLSSTL,CLASS *GET,VALUE( 1,2),ELEM,1,ETAB,CLASS_J ~PLLSSTL,ALP_Z *GET,VALUE( 2,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,AREA *GET,VALUE( 3,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,LAM_Z *GET,VALUE( 4,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,PHI_Z *GET,VALUE( 5,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,CHI_Z *GET,VALUE( 6,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,NBRD *GET,VALUE( 7,2),ELEM,1,ETAB,CFETAB_J ~PLLSSTL,CRT_TOT *GET,VALUE( 8,2),ELEM,1,ETAB,CFETAB_J ! Warning and error tolerances TOLER( 1,1)= 1 $ TOLER( 1,2)= 1 TOLER( 2,1)= 1E-2 $ TOLER( 2,2)= 1E-1 TOLER( 3,1)= 1E-4 $ TOLER( 3,2)= 1E-3 TOLER( 4,1)= 1E-2 $ TOLER( 4,2)= 1E-2 TOLER( 5,1)= 1E-2 $ TOLER( 5,2)= 1E-1 TOLER( 6,1)= 1E-3 $ TOLER( 6,2)= 1E-2 TOLER( 7,1)= 1 $ TOLER( 7,2)= 1E1 TOLER( 8,1)= 1E-2 $ TOLER( 8,2)= 1E-1 !-------------------------------------------------------------------------------------- ! Results comparison !-------------------------------------------------------------------------------------- COMPARA.MAC |
Results
| Label | Target | CivilFEM | Ratio | Tolerance |
| CLASS | 3 | 3 | 1.000 | 1 |
| ALP_Z | 0.34 | 0.34 | 1.000 | 0.1 |
| AREA | 0.002271 | 0.002271 | 1.000 | 0.001 |
| LAM_Z | 4.9337 | 4.933 | 1.000 | 0.01 |
| PHI_Z | 13.47 | 13.472 | 1.000 | 0.1 |
| CHI_Z | 0.03844 | 0.038449 | 1.000 | 0.01 |
| NBRD | 38.25 | 38.254 | 1.000 | 10 |
| CRT_TOT | 6.53 | 6.5353 | 0.999 | 0.1 |
Contains proprietary and confidential information of Ingeciber, S.A.

